Given, ABC is a triangle, right-angled at C as shown below.
ABC is a triangle, right-angled at C. If AB = 25 cm and AC = 7 cm, find BC
So, we can apply the Pythagoras theorem here, if it is right-angled at C then the side opposite to C will be the hypotenuse of the triangle that is AB = 25 cm, and the other two sides are AC = 7 cm and BC.
Now, by applying the Pythagoras theorem i.e. in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides, we can find BC.
AB = 25 cm, AC = 7 cm and BC =?
In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2
(AB)2 = (AC)2 + (BC)2
(25)2 = (7)2 + (BC)2
625 = 49 + (BC)2
(BC)2 = 625 – 49
(BC)2 = 576
BC = 24 cm
Thus, BC is equal to 24cm
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