The electric field in front of the wall will be 4.61 × 10⁹ N/C.
An electrostatic force is a natural environment that covers electric polarization and acts as an attractor or repellent to all other energetic particles in the vicinity. It can also refer to a network of charged particles' test performance.
The electric field is given as,
E = σ / 2ε₀
Where σ is the charge per unit area, ε is the permeability (8.85 x 10⁻¹² N-m² / C²).
A non-conducting wall carries a charge with a uniform density of 8.15 µc / square cm.
The charge per unit area of the wall will be
σ = 8.15 × 10⁻⁶ C/cm²
σ = (8.15 × 10⁻⁶ C/cm²) × (100 cm / m)²
σ = 8.15 × 10⁻² C/m²
Then, at a distance of 2.00 cm, the electric field will be
E = 8.15 × 10⁻² / 2(8.85 x 10⁻¹²)
E = 4.61 × 10⁹ N/C.
The electric field in front of the wall will be 4.61 × 10⁹ N/C.
More about the electric field link is given below.
https://brainly.com/question/15800304
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