Respuesta :
the no. of Al atoms required to be laid side by side to make up a distance of 4.23 mm is = 4.23/(2 * 143 * 10^(-9) )
= 14790210 atoms of Al.
What is the radius of an atom?
The atomic radius of an atom is the distance between the centre of the nucleus and the outermost electron in each of its energy shells. Since the border is not a clearly defined physical entity, there are many non-equivalent definitions of atomic radius. The four most popular ways to define atomic radius are van der Waals radius, ionic radius, metallic radius, and covalent radius. Due to the challenges of isolating individual atoms to measure their radii, atomic radii are frequently measured in a chemically bonded state; yet, theoretical calculations are simpler when individual atoms are taken into account.
1 pm = 10^(-9) mm
radius of Al atom = 143 pm = 143 * 10^(-9) mm
Diameter of Al atom = 2 * 143 * 10^(-9) mm
Thus, the no. of Al atoms required to be laid side by side to make up a distance of 4.23 mm is = 4.23/(2 * 143 * 10^(-9) )
= 14790210 atoms of Al.
To learn more about radius of an atom from the given link below,
https://brainly.com/question/10534465
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