Respuesta :
With the help of Equations of Kinematics, we can say that, both the stones meet at a time t= 4 seconds and they meet at a height of 320 meters from the ground if the speed of the second stone was 100ms⁻¹.
How does a body in motion act under the influence of gravity?
When the body is thrown upwards or downwards it is influenced by gravity and it accelerates and deaccelerates accordingly and its magnitude is equal to the Acceleration due to gravity (g).
Based on this concept, if the body is thrown upwards a = - g (deacceleration), and if the body is dropped downwards a = g(acceleration).
Here in this question, the stone thrown upwards will deaccelerate and the one dropped downwards will accelerate.
So, the Height of the tower=400 meters.
Let the distance traveled by the stone dropped downwards from the top be s₁ and the distance traveled by the stone thrown upwards from the bottom be s₂.
Let the initial velocity of stone dropped downwards be u₁ and the stone is thrown upwards be u₂.
Let the time at which they meet together be t.
Now, using the equation of kinematics,
s=ut+ 1/2gt²
Here, acceleration = a will be equal to the acceleration due to gravity g.
(Take g=10m/s²).
We can write,
s₁=u₁t+1/2 gt²
s₂=u₂t-1/2 gt²
We know that,
s₁+s₂= 400
So, substituting the values of s₁ and s₂
u₁t+1/2 gt² + u₂t-1/2 gt² = 400
As the stone was dropped from rest u₁=0
On further solving,
u₂t=400
Given, u₂= 100ms⁻¹
Hence, t=4 s
Now, s₂= 100(4)-1/2(10)(4²)
=400 - 80
= 320 m
The distance is 320 m from the ground.
To know more about Equations of Kinematics visit: https://brainly.com/question/14355103
#SPJ4
