a​ company's charge for electricity is ​¢6.434 per​ kilowatt-hour. in​ addition, each monthly bill contains a customer charge of ​$7.81. if last​ year's bills ranged from a low of ​$51.74 to a high of ​$​192.28, over what range did usage vary​ (in kilowatt-hours)? course hero

Respuesta :

The range in which the usage vary is from 682.77  kilowatt-hours to 2867.11  kilowatt-hours.

Given the charge of electricity charge is 6.434 cents  per​ kilowatt-hour.

Fixed customer charge = ​$7.81

Bill range = $51.74 to ​$​192.28

Since every value is in $ , we will first convert cents to dollar

per​ kilowatt-hour charge will be $6.434/100    ( as $1 = 100 cents )

per​ kilowatt-hour charge = $ 0.06434    …(1)

Lets us first find the lower range of usage

Last year's lowest bill was $51.74 (including the customer charge)

So last year lowest bill = $51.74-$7.81  = $43.93   …(2)

We know that (per KWh charge)x(no. of KWh used)=Total bill. …(3)

Substituting the values from (1) & (2) we get

(0.06434)x(no. of KWh used)=$43.93

no. of KWh used=[tex]\frac{43.93}{0.06434} = 682.77 KWh[/tex]

Similarly we will solve for maximum KWh used

Lets us find the maximum range of usage

Last year's highest bill was $192.28 (including the customer charge)

So last year highest bill = $192.28-$7.81  = $184.47   …(4)

Substituting the value of (1) & (4) in (3) we get

(0.06434)x(no. of KWh used)=$184.47

no. of KWh used=[tex]\frac{184.47}{0.06434} =2867.11 KWh[/tex]

Therefore ,  the The range in which the usage vary is from 682.77 kilowatt-hours to 2867.11  kilowatt-hours.

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