The perimeter of the given figure for the given values is equal to 24units.
As given in the question,
Given values of the figure,
AB = 8 cm, BC = 3 cm, CD = 1 cm, DE = 2 cm, EF = 3 cm, and FG = 1 cm
HG = AB - (EF + CD)
= 8- (3 +1)
= 4 units
AH = (BC-DE)+FG
= (3-2)+1
=2units
Perimeter of the given figure
= AB + BC+ CD+ DE+ EF+ FG+ GH+ HA
= 8+ 3+ 1+ 2+ 3+ 1+ 4+ 2
=24 units
Therefore, the perimeter of the given figure for the given values is equal to 24units.
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