If we want to estimate 97% confidence interval for the true proportion of Americans who support gun control in 2019 with a 0.27 margin of error, then 16 Americans must be surveyed.
Given,
The confidence level =97%
Critical z value of 97% confidence interval =2.170
Margin error E= 0.27
We know,
Sample size n= [tex]0.25(\frac{z}{E})^{2}[/tex]
Substitute the values in the equation
[tex]n=0.25(\frac{2.170}{0.27})^{2}\\ n=0.25( 8.03)^{2}[/tex]
n=16.12
n≈16
Hence, if we want to estimate 97% confidence interval for the true proportion of Americans who support gun control in 2019 with a 0.27 margin of error, then 16 Americans must be surveyed.
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