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tin(iv) sulfide, sns2, a yellow pigment, can be produced using the following reaction. snbr4(aq) 2na2s(aq)⟶4nabr(aq) sns2(s) suppose a student adds 35.2 ml of a 0.419 m solution of snbr4 to 51.1 ml of a 0.203 m solution of na2s.

Respuesta :

The theoretical yield of SnS₂ will be 4.20 gram can be produced using the following reaction

From the equation of the reaction:

The mole ratio of the reactant is 1:2.

Mole of 35.2 mL, 0.419 M SnBr₄  = 0.419 x 35.2/100 = 0.147 mols

Mole of 51.1 mL, 0.203 M Na₂S = 0.203 x 51.1/1000 = 0.0103 moles

Thus, Na₂S is in excess while SnBr4  is limiting.

Mole ratio of SnBr₄  and SnS₂ = 1:1

Equivalent mole of SnS₂ = 0.023 moles

Mass of 0.023 moles SnS₂ = 0.023 x 182.81 = 4.20 grams

Theoretical Yield Formula :

The quantity of a product obtained from a reaction which is expressed in terms of the yield of the reaction. the quantity of product predicted by stoichiometry is called the theoretical yield, whereas the quantity obtained actually is called the actual yield.

Is theoretical yield the limiting reactant?

A limiting reagent may be a chemical reactant that limits the amount of product that is formed. The limiting reagent gives the littlest yield of product calculated from the reagents (reactants) available. This smallest yield of product is named the theoretical yield.

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