The magnitude of force required to apply 130 n.m of torque to the bolt is 722.
f = magnitude of force
F = Vector force.
F = f [(0 i + 4 j - 3 k)] (02 + 42 + (-3)2)) = (f/5) (4 j - 3 k)
r = 30 cm = 0.30 m
[tex]\tau[/tex] = Torque = 130
Using the formula
[tex]\tau[/tex] = r x F
130 = (0.30 j) x (f/5) (4 j - 3 k)
130 = (f/5) (-0.9 i)
f = 130 x 5 /0.9 = 722
Hence, 722 is the magnitude of the force needed to supply 130 n.m of torque to the bolt.
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