The thickness of the aluminum foil in millimeters is 0.0147 mm
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
Density = mass / volume
Thus,
Volume = mass / density
Volume of aluminum = 3.686 / 2.699
Volume of aluminum = 1.366 cm³
Divide by 28316.8 to express in ft³
Volume of aluminum = 1.366 / 28316.8
Volume of aluminum = 4.82×10⁻⁵ ft³
Volume = area × thickness
Divide both sides by area
Thickness = volume / area
Thickness = 4.82×10⁻⁵ / 1
Thickness = 4.82×10⁻⁵ ft
Multiply 304.8 to express in mm
Thickness = 4.82×10⁻⁵ × 304.8
Thickness = 0.0147 mm
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Complete question
A sheet of aluminum foil has a total area of 1.000ft2and a mass of 3.686g. What is the thickness of the foil inmillimeters? (The density of aluminum is 2.699g/cm3)
