The minimum diameter of a steel wire if it is to support a mass of 80 kg is 1.41 * 10⁻³ m.
What will be the minimum diameter of a steel wire if it is to support a mass of 80 kg?
The minimum diameter, d of the steel wire can be calculated thus:
α = 5.0 × 10⁸ Pa.
mass, m = 80 kg
Force = 80 * 98 = 784 N
Area = force/α
area = 784/5.0 × 10⁸
area = 1.57 * 10⁻⁶
Area = πd²/4
d = √(4 * area/π)
d = √(4 * 1.57 * 10⁻⁶ * 7/22)
diameter = 1.41 * 10⁻³ m
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Note that the complete question is given below:
What is the minimum diameter of a steel wire if it is to support a mass of 80 kg? The elastic limit of steel is 5.0 × 10⁸ Pa.
