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The empirical formula of the compound is CH₃N

How to determine the mass of Carbon

  • Mass of CO₂ = 53 mg
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 53

Mass of C = 14.45 mg

How to determine the mass of H

  • Mass of H₂O = 32.6 mg
  • Molar mass of H₂O = 18 g/mol
  • Molar of H = 2 × 1 = 2 g/mol
  • Mass of H =?

Mass of H = (2 / 18) × 32.6

Mass of H = 3.62 mg

How to determine the mass of N

  • Mass of compound = 35 mg
  • Mass of C = 14.45 mg
  • Mass of H = 3.62 mg
  • Mass of N =?

Mass of N = (mass of compound) – (mass of C + mass of H)

Mass of N = 35 – (14.45 + 3.62)

Mass of N = 16.93 mg

How to determine the empirical formula

  • C = 14.45 mg
  • H = 3.62 mg
  • N = 16.93 mg
  • Empirical formula =?

Divide by their molar mass

C = 14.45 / 12 = 1.204

H = 3.62 / 1 = 3.62

N = 16.93 / 14 = 1.209

Divide by the smallest

C = 1.204 / 1.204 = 1

H = 3.62 / 1.204 = 3

N = 1.209 / 1.204 = 1

Thus, the empirical formula of the compound is CH₃N

Learn more about empirical formula:

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