The angular velocity is θ" = 0.302rad/s
Given data,
r = 100cos(2θ)
r = -200sin(2θ)θ"
For angular velocity,
[tex]v = \frac{dr}{dt} u^{r} +r\frac{dθ}{dt}[/tex]
[tex]v = \sqrt{\frac{dr}{dt} } ^{2} + \sqrt\frac{rdθ}{dt} ^{2}[/tex]
So, v = 20m/s
20 = √[-200sin(2θ)θ"[tex]]^{2}[/tex] + √[100cos(2θ)θ"[tex]]^{2}[/tex]
400 = [-200sin(2×15)θ"[tex]]^{2}[/tex] + [100cos(2×15)θ"[tex]]^{2}[/tex]
On solving for angular velocity, we get
θ" = 0.302rad/s
Learn more about angular velocity here;
https://brainly.com/question/12446100
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