An opaque bag contains 22 yellow marbles and 11 teal marbles. if two marbles are randomly chosen from the bag at the same time, find the probability that both marbles are teal. round your answer to four decimal places.

Respuesta :

If two marbles are randomly chosen from the bag contains 22 yellow marbles and 11 teal marbles, then the probability that the both marbles are teal is [tex]\frac{10}{99}[/tex]

Given,

The number of yellow marbles = 22

Number of teal marbles = 11

Total number of marbles = 22+11= 33 marbles

Then two marbles are chosen randomly

We know,

The probability = Number of favorable outcomes/ Total outcomes

Probability that first marble is teal =[tex]\frac{11}{33}[/tex]=[tex]\frac{1}{3}[/tex]

Probability that second marble is teal =[tex]\frac{10}{33}[/tex]

Here we are considering without replacement

Then the probability that both marbles are teal = [tex](\frac{1}{3})(\frac{10}{33})=\frac{10}{99}[/tex]

Hence, if two marbles are randomly chosen from the bag contains 22 yellow marbles and 11 teal marbles, then the probability that the both marbles are teal is [tex]\frac{10}{99}[/tex]

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