If two marbles are randomly chosen from the bag contains 22 yellow marbles and 11 teal marbles, then the probability that the both marbles are teal is [tex]\frac{10}{99}[/tex]
Given,
The number of yellow marbles = 22
Number of teal marbles = 11
Total number of marbles = 22+11= 33 marbles
Then two marbles are chosen randomly
We know,
The probability = Number of favorable outcomes/ Total outcomes
Probability that first marble is teal =[tex]\frac{11}{33}[/tex]=[tex]\frac{1}{3}[/tex]
Probability that second marble is teal =[tex]\frac{10}{33}[/tex]
Here we are considering without replacement
Then the probability that both marbles are teal = [tex](\frac{1}{3})(\frac{10}{33})=\frac{10}{99}[/tex]
Hence, if two marbles are randomly chosen from the bag contains 22 yellow marbles and 11 teal marbles, then the probability that the both marbles are teal is [tex]\frac{10}{99}[/tex]
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