If Katie invested a total of $8000, part at 5% simple interest and part at 6% simple interest and at the end of one year the investments had earned $454 interest, then she invested $2600 at 5% and $5400 at 6% simple interest
Given,
The total invested amount = $8000
Consider the amount invested at 5% simple interest as x and the amount invested at 6% simple interest as y
Then, the equations will become
x + y= 8000
x = 8000-y
At the end of one year the investment = $454
0.05x + 0.06y =454
Substitute the value of x in the equation
0.05(8000-y) + 0.06y =454
400-0.05y+0.06y =454
0.01y+400=454
0.01y =54
y = 5400
Substitute the value of x in
x + y = 8000
x+5400=8000
x=8000-5400
x=2600
Hence, if Katie invested a total of $8000, part at 5% simple interest and part at 6% simple interest and at the end of one year the investments had earned $454 interest, then she invested $2600 at 5% and $5400 at 6% simple interest
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