Respuesta :
When Angelo drove home from college with an average speed of 71.7 mph and back to college with an average speed of 64.1 mph, she took 5 hours for full trip then the time taken to travel from home to college is 2.63 hours
Given,
The average speed from college to home = 71.7 mph
The average speed from home to college = 64.1 mph
We know,
Speed = Distance / Time
Consider the total distance as x
Time taken = Distance / Speed
Then the time taken to travel from college to home = [tex]\frac{x}{71.7}[/tex] hours
time taken to travel from home to college = [tex]\frac{x}{64.1}[/tex] hours
Total time taken = 5 hours
Then the equation will become
[tex]\frac{x}{71.7}+\frac{x}{64.1}=5[/tex]
Cross multiply the terms
[tex]\frac{64.1x+71.7x}{(71.7)(64.1)}=5\\ \frac{135.8x}{4595.97}=5[/tex]
135.8x= 5×4595.97
135.8x=22979.85
x=169.21
Time taken to travel from home to college =[tex]\frac{169.21}{64.1}[/tex]
=2.63 hours
Hence, When Angelo drove home from college with an average speed of 71.7 mph and back to college with an average speed of 64.1 mph, she took 5 hours for full trip, then the time taken to travel from home to college is 2.63 hours
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