What is a polynomial function in standard form with zeros 1,-1, 2, and 4?
○_A. y = x¹ − 6x³ + 7x² + 6x − 8
O B. y = x² - 6x³ + 9x² + 6x-8
OC. y = x³ + 7x² + 6x - 8
OD. y = x - x³ + x²+x-8

Respuesta :

The equation using the polynomial function is a x⁴ - 6x³ + 7x² + 6x - 8.

According to the statement

We have to find that the equation using the polynomial function.

So, For this purpose, we know that the

A polynomial function is a function that involves only non-negative integer powers or only positive integer exponents of a variable in an equation

From the given information:

The standard form with zeros 1,-1, 2, and 4:

Polynomial with Zeros 1, - 1, 2 and 4 can be expressed thus :

x = 1 : x - 1

x = - 1 :x + 1

x = 2 :x - 2

x = 4 :x - 4

Hence, we have :

(x - 1)(x + 1)(x - 2)(x - 4) = 0

We can then expand ;

(x - 1)(x + 1) = x² + x - x - 1 = x² - 1

(x² - 1)(x - 2) = x³ - 2x²-x + 2

(x³ - 2x² - x + 2)(x - 4)

x⁴ - 4x³ - 2x³ + 8x² - x² + 4x + 2x - 8

x⁴ - 6x³ + 7x² + 6x - 8.

So, The equation using the polynomial function is a x⁴ - 6x³ + 7x² + 6x - 8.

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