The we can draw a rectangle with length = 2 cm and width = 4 cm.
According to the statement
We have to find that the dimensions of the another rectangle.
So, For this purpose, we know that the
A Rectangle is a four sided-polygon, having all the internal angles equal to 90 degrees.
From the given information:
The perimeter of a pool is 150 m. The rectangle at the right is a scale drawing of the pool. The length of each square on the grid represents 1 cm. Draw another scale drawing of the pool using the scale 25 m to 2 cm.
Then
From the given rectangle,
Length of the rectangle = 5 cm
Width of the rectangle = 10 cm
Ratio of length : width = 1 : 2
Perimeter of the rectangle = 2(l + b)= 150 cm
l + b = 75 -----(1)
Since, l : b = 1 : 2
b = 2l ------(2)
From equations (1) and (2),
l + 2l = 75
3l = 75
l = 25 m
Width 'b' = 2(25) = 50 m
Now we have to draw a rectangle with a scale = 25 : 2
Therefore, Scale factor = 25/l = 25/2
Scale factor = l = 2cm
Then Similarly,
50/ w= 50/2
w = 4cm
Now we can draw a rectangle with length = 2 cm and width = 4 cm.
So, The we can draw a rectangle with length = 2 cm and width = 4 cm.
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