The true statements are f(-5) = -40, f(0) = 3 and f(3) = 0
Given the function;
f(a) = 3a – a2
For f(-5), we substitute the value of a as -5, we have
f(-5) = 3(-5) - (-5)²
f(-5) = -15 - 25
f(-5) = -40
For f(4), we have
f(4) = 3(4) = 3(16)
f(4) = 12 - 48
f(4) = -36
For f(-1), we have
f(-1) = 3(-1) - (-1)²
f(-1) = -3 - 1
f(-1) = -4
For f(0), we have
f(0) = 3(0) -(0)
f(0) = 0
For f(3), we have
f(3) = 3(3) - 3²
f(3) = 0
Thus, the true statements are f(-5) = -40, f(0) = 3 and f(3) = 0
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