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A race car is one lap behind the lead race car when the lead car has 52 laps to go in a race. If the speed of the lead car is 56.3 m/s, what must be the average speed of the second car to catch the lead car just before the end of the race, assume 1 lap is 1.34km

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The speed of the car is 55.2 m/s.

What is the average speed?

We can define speed as the ratio of distance to time. We know that the question states the car is one lap behind the lead race car when the lead car has 52 laps to go in a race.

If 1 lap =  1.34km or 1340 m

Distance covered =   1340 m * 52 = 69680 m

Time = 69680 m/ 56.3 m/s

= 1237.7 s

Given that the second car is one lap behind;

51 *  1340 m = 68340 m

Speed =  68340 m/1237.7 s

= 55.2 m/s

Learn more about speed:https://brainly.com/question/28224010

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