The fluid force against the window is equal to 931.5 lb.
Given the following data:
- Width of viewing portion = 69 inches.
- Dimension of fish tank = 69 × 28.5 × 1.5 inches.
- Density of seawater = 64 lb/ft.
- Thickness of glass = 3/4 inch.
How to calculate the fluid force against the window?
Generally speaking, the fluid force that is exerted on the fish tank by the seawater is due to the liquid pressure acting over the given area. Also, the fluid force that is exerted on the fish tank is directly proportional to the depth of seawater.
The depth of seawater is given by:
Depth = 28.5 - 1.5
Depth = 27 inches.
Next, we would convert the unit of the depth of seawater and width of viewing portion in inches to feet:
1 inch = 12 feet
Depth = 27 inches to feet = 27/12 = 2.25 feet.
Width = 69/12 = 5.75 feet.
Now, we can calculate the fluid force against the window by using this formula:
Fluid force = (density × depth × width)/2
Fluid force = (64 × 2.25² × 5.75)/2
Fluid force = 1863/2
Fluid force = 931.5 lb.
Read more on fluid force here: https://brainly.com/question/13090061
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Complete Question:
The viewing portion of the rectangular glass window in a fish tank is 69 inches wide and runs from 1.5 inches below the water's surface to 28.5 inches below the surface. Find the fluid force against this portion of the window. The weight-density of seawater is 64 lb/ft. What is the fluid force against the window?
