To distinctly address 226kb in a byte addressable memory, one would need 8 bits.
What is an addressable memory?
Word addressing in computer architecture implies that addresses of memory on a computer authenticate words of memory.
In contrast to byte addressing, where addresses authenticate bytes, it is commonly employed.
What is the calculation justifying the above answer?
Given:
2⁸ = 256
and 226 < 256
Hence, we need 8 bit.
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