Answer: y<3x-4
Step-by-step explanation:
[tex](0,-4) \ \ \ \ \ \ (1,-1)[/tex]
The equation of the line
[tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]
[tex]\displaystyle\\x_1=0\ \ \ \ x_2=1\ \ \ \ y_1=-4\ \ \ \ y_2=-1\\Hence,\\\frac{x-0}{1-0} =\frac{y-(-4)}{-1-(-4)} \\\\\frac{x}{1} =\frac{y+4}{-1+4} \\x=\frac{y+4}{3}[/tex]
Умножьте обе части уравнения на 3:
[tex]3x=y+4\\3x-4=y+4-4\\3x-4=y[/tex]
Thus, y<3x-4
