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If 39% of the body weight is distributed above the superior surface of the L5 intervertebral disc and the area of the superior surface of the disc is 25 cm2, how much pressure on the disc is attributable to body weight for a 1000 N man?

Respuesta :

Eduard22sly

The pressure on the disc attributed to body weight for a 1000 N man is 120000 N/m²

Formula for pressure

P = F / A

Where

  • P is the pressure
  • F is the force
  • A is the area

Data obtained from the question

The following data were obtained from the question:

  • Area (A) = 25 cm² = 25 × 0.0001 = 0.0025 m²
  • Weight = 1000 N
  • Force (F) = 30% of weight = 30% × 1000 = 300 N
  • Pressure (P) =?

How to determine the pressure

The pressure can be obtained as follow:

P = F / A

P = 300 / 0.0025

P = 120000 N/m²

Thus, the pressure on the disc is 120000 N/m²

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