The probability that no Tails is achieved on flipping a fair coin for three consecutive times is [tex](\frac{1}{8})[/tex].
As per the question statement, we are to flip or toss a fair coin thrice consecutively.
We are required to calculate the probability that no Tails is achieved during the above mentioned event.
To solve this question, first let us calculate all the possible outcomes of flipping a fair coin thrice consecutively. [We will denote a Heads outcome as "H" and a Tails outcome as "T"]
The total number of outcomes can be given by the formula [tex](2^{n})[/tex], where "n" is the number of times, the coin is tossed.
Here, (n = 3), therefore, total number of outcomes in our case [tex]=(2^{3})=8[/tex].
These 8 outcomes can be listed as [tex][{(H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T)}][/tex]
And among the above listed 8, our favorable outcome is (H, H, H), i.e., 1 favorable outcome of 8.
Hence, probability that no Tails is achieved on flipping a fair coin thrice consecutively = [tex]\frac{1}{8}[/tex].
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