Using the normal distribution, the standard deviation of bone density in the reference population is of 5.52 g/cm².
The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
For this problem, the parameters are given as follows:
[tex]X = 948, z = -1.45, \mu = 956[/tex]
Hence we solve for [tex]\sigma[/tex] to find the z-score as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.45 = \frac{948 - 956}{\sigma}[/tex]
[tex]-1.45\sigma = -8[/tex]
[tex]\sigma = \frac{8}{1.45}[/tex]
[tex]\sigma = 5.52[/tex]
The standard deviation of bone density in the reference population is of 5.52 g/cm².
More can be learned about the normal distribution at https://brainly.com/question/24808124
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