Answer:
(a) 3.5
(b) x = 4
(c) -¹/₂
(d) -¹/₂
Step-by-step explanation:
Part (a)
f(1) is the value of y when x = 1.
To find the value of y from a given value of x, find the position of x on the x-axis, then trace vertically until you meet the line. Once you meet the line, trace horizontally to the y-axis to find the corresponding value of y.
Therefore, f(1) = 3.5.
Part (b)
To solve f(x) = 2, find the value of x when y = 2.
To find the value of x from a given value of y, find the position of y on the y-axis, then trace horizontally until you meet the line. Once you meet the line, trace vertically to the x-axis to find the corresponding value of x.
Therefore, the solution of f(x) = 2 is x = 4.
Part (c)
The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:
[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]
Given interval: 2 ≤ x ≤ 4
Therefore:
[tex]\implies \dfrac{f(4)-f(2)}{4-2}=\dfrac{2-3}{4-2}=-\dfrac{1}{2}[/tex]
Part (d)
The average rate of change between any interval of the given function will be the same as the graph is linear. Therefore, the average rate of change from 0 to 8 is the same as the rate found in part (c): -¹/₂.
Proof
The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:
[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]
Given interval: 0 ≤ x ≤ 8
Therefore:
[tex]\implies \dfrac{f(8)-f(0)}{8-0}=\dfrac{0-4}{8-0}=-\dfrac{4}{8}=-\dfrac{1}{2}[/tex]
