The cost of 4 boxes of pens and 3 boxes of pencils is $22.55. The cost of 3 boxes of pens and 2 boxes of pencils is $16.45. Find the cost of each.

Respuesta :

Answer:

One pen is $4.25 and one pencil is $1.85.

Step-by-step explanation:

Let cost of pens be x and cost of pencils be y.

1. 4x+3y=22.55

2. 3x+2y=16.45

Sub. 1.-2.,

x+y=22.55-16.45

x=6.1-y

Sub. x=6.1-y into 1.,

y=1.85

x=4.25

Answer:

Cost of a box of pens = $4.25

Cost of a box of pencils = $1.85

Step-by-step explanation:

Given information:

  • Cost of 4 boxes of pens and 3 boxes of pencils = $22.55
  • Cost of 3 boxes of pens and 2 boxes of pencils = $16.45

Define the variables:

  • Let x = the cost of a box of pens.
  • Let y = the cost of a box of pencils.

Create two equations from the given information:

[tex]\textsf{Equation 1}: \quad 4x + 3y = 22.55[/tex]

[tex]\textsf{Equation 2}: \quad 3x + 2y = 16.45[/tex]

Multiply Equation 1 by 3:

[tex]\implies 3 \cdot 4x + 3 \cdot 3y = 3 \cdot 22.55[/tex]

[tex]\implies 12x + 9y = 67.65[/tex]

Multiply Equation 2 by 4:

[tex]\implies 4 \cdot 3x + 4 \cdot 2y = 4 \cdot 16.45[/tex]

[tex]\implies 12x + 8y = 65.80[/tex]

Subtract the equations to eliminate the term in x:

[tex]\begin{array}{r rr}& 12x+9y = &67.65\\- & 12x+8y = &65.80\\\cline{2-3} & y = & 1.85\end{array}[/tex]

Substitute the found value of y into one of the equations and solve for x:

[tex]\implies 3x + 2y = 16.45[/tex]

[tex]\implies 3x + 2(1.85) = 16.45[/tex]

[tex]\implies 3x + 3.7 = 16.45[/tex]

[tex]\implies 3x =12.75[/tex]

[tex]\implies x=4.25[/tex]

Solution

  • Cost of a box of pens = $4.25
  • Cost of a box of pencils = $1.85

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