16. A collection of dimes and nickels is worth $3.10. If there are 45 coins in all, how many of each kind of coin are there?

Respuesta :

Answer:

28 nickels and 17 dimes

Step-by-step explanation:

A nickel is worth 5 cents and a dime is worth 10 cents

If there are X nickels and Y dimes

Total value = 5X + 10Y cents

$3.10 == 3.10 x 100 = 310 cents

So 5X + 10 Y = 310

Divide both sides by 5 to get

5X/5 + 10Y/5 = 310/5

X + 2Y = 62  (1)

The total number of coins is X + Y and is given to be 45

X + Y = 45    (2)

Subtract Eq(2) from Eq(1) to get

X + 2Y - (X + Y) = 62-45 = 17

X + 2Y - X - Y = 17

Collecting like terms

(X - X) + (2Y - Y) = 17

Y = 17

So number of dimes = 17

To find X, the number of nickels use equation (2)

X + 17 = 45

Subtract 17 from both sides

X + 17 - 17 = 45 - 17

X = 28

So number of nickels = 28