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A 2.300 −g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854 kJ/∘C . The temperature of the calorimeter increases from 24.64 ∘C to 32.09 ∘C .What is the heat of combustion per gram of quinone?

Respuesta :

bharathparasad577

The heat of combustion per gram of quinone is -25.43 KJ/g.

  • A constant-volume bomb calorimeter can be used to calculate a substance's heat of combustion. The heat absorbed by the bomb calorimeter can be compared to the heat emitted by the reaction. Additionally, it is necessary to understand the calorimeter's heat capacity.
  • - Q(rxn) = Q(cal) = C(cal)ΔT

Given,

mass of sample = 2.300g

total heat capacity = 7.854 kJ/∘C

Temperature change = 32.09 - 24.64 = 7.45

we have to find out heat of combustion per gram of quinone.

- Q(rxn) = Q(cal) = C(cal)ΔT

Q(rxn) = -(7.854kJ/⁰C)(32.09 - 24.64)

= -58.5 KJ

Now, we will calculate heat of combustion per gram.

Q(rxn) = -58.5/2.3g = -25.43 KJ/g

negative sign denote exothermic reaction.

Thus, heat of combustion per gram of quinone is -25.43 KJ/g.

Learn more about heat of combustion here:

https://brainly.com/question/25312146

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