A 1.2kg stone is tied to string and swung in a vertical circle with a radius of 0.85 m. The string can withstand a tension of 40.0 N. At the maximum speed can the stone move at the bottom of its path without the string breaking

Respuesta :

The maximum speed of the stone tied to the string is 5.32 m/s.

The mass of the stone is m = 1.2 kg.

The mass is tied to a string and it swung in a vertical radius of r = 0.85 cm.

The tension on the string is T = 40 N.

The centripetal force of a body moving in a circle of radius r is given as:

T = ( mv² / r )

Where T is the tension, m is the mass of the body and r is the radius of the circle.

Then,

v² = ( T × r ) / m

v = √ [ T × r / m ]

v = √ [ 40 × 0.85 / 1.2 ]

v = √ [ 34 / 1.2 ]

v = √28.3

v = 5.32 m/s

The maximum speed of the stone before the string breaks is 5.32 m/s.

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