The shape of a dome can be
modeled by the equation h =
- 2d^2 + 100 where h is the height
(in feet) of the dome from the
floor d feet from its center. How
far from the center of the dome
is the height 50 feet?

Respuesta :

Answer:

5 feet

Step-by-step explanation:

We are told that the height of the dome can be modelled by the equation:

[tex]\boxed{h = -2d^2 + 100}[/tex]

The question is essentially asking us: for what value of d will the value of h be 50 feet?

To solve this, we have to substitute h in the equation with 50 and then solve for d.

∴ [tex]50 = -2d^2 + 100[/tex]

⇒ [tex]50 + 2d^2 + 100[/tex]

⇒ [tex]2d^2 = 100 - 50[/tex]

⇒ [tex]d^2 = \frac{100 - 50}{2}[/tex]

⇒ [tex]d^2 = 25[/tex]

⇒ [tex]d = \sqrt{25}[/tex]

⇒ [tex]d = \bf 5[/tex]

This means that 5 feet from the center of the dome, the height of the dome is 50 feet.