Answer:
Solutions of the quadratic equation are [tex]\dfrac{2}{3},\dfrac{1}{2}[/tex]
Step-by-step explanation:
The given quadratic equation is,
[tex]6x^2 - 7x + 2 = 0[/tex]
The quadratic formula is,
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Here,
[tex]a = 6,b=-7,c=2[/tex]
Putting the values,
[tex]x=\dfrac{-(-7)\pm \sqrt{(-7)^2-4\cdot 6\cdot 2}}{2\cdot 6}[/tex]
[tex]=\dfrac{7\pm \sqrt{49-48}}{12}[/tex]
[tex]=\dfrac{7\pm \sqrt{1}}{12}[/tex]
[tex]=\dfrac{7\pm 1}{12}[/tex]
[tex]=\dfrac{7+ 1}{12},\dfrac{7-1}{12}[/tex]
[tex]=\dfrac{8}{12},\dfrac{6}{12}[/tex]
[tex]=\dfrac{2}{3},\dfrac{1}{2}[/tex]
