If 30.0 ml of 0.15 m ba(oh)2 was needed to neutralize 50.0 ml of an h3po4 solution. what is the concentration of the original h3po4 solution?

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If 30.0 ml of 0.15 m ba(oh)2 was needed to neutralize 50.0 ml of an h3po4 solution. what is the concentration of the original h3po4 solution?

Barium hydroxide is a strong diprotic base and phosphoric acid is a weak triprotic acid. Therefore the balanced acid-base reaction requires a 3:2 molar ratio:

3Ba(OH)2+2H3PO4→Ba3(PO4)2+6H2O

First we find the moles of barium hydroxide reactant:

Volume of barium hydroxide (given) = V1=0.0300 L

Molarity of barium hydroxide (given) = C1=0.15 M

Moles of barium hydroxide = n1=V1×C1=0.0045 mol

For neutralization we require 2/3 the moles for phosphoric acid:

Moles of phosphoric acid = n2=23×0.0045 mol=0.0030 mol

Volume of phosphoric acid (given) = V2=0.0500 L

Molarity of phosphoric acid = n2V2=0.0030 mol/0.0500 L=0.060M

What is Neutralization Reaction?

Conjugate base and acid are the results of the reaction between a Bronsted acid (proton donor) and a Bronsted base (proton acceptor). When both of these reactants have been completely consumed, leaving only the product species, a neutralisation reaction takes place. The stoichiometry of the balanced acid-base reaction equation is used to determine the ratio of molar amounts needed for neutralisation.

Therefore,

If 30.0 ml of 0.15 m ba(oh)2 was needed to neutralize 50.0 ml of an h3po4 solution. what is the concentration of the original h3po4 solution?

Barium hydroxide is a strong diprotic base and phosphoric acid is a weak triprotic acid. Therefore the balanced acid-base reaction requires a 3:2 molar ratio:

3Ba(OH)2+2H3PO4→Ba3(PO4)2+6H2O

First we find the moles of barium hydroxide reactant:

Volume of barium hydroxide (given) = V1=0.0300 L

Molarity of barium hydroxide (given) = C1=0.15 M

Moles of barium hydroxide = n1=V1×C1=0.0045 mol

For neutralization we require 2/3 the moles for phosphoric acid:

Moles of phosphoric acid = n2=23×0.0045 mol=0.0030 mol

Volume of phosphoric acid (given) = V2=0.0500 L

Molarity of phosphoric acid = n2V2=0.0030 mol/0.0500 L=0.060M

To learn more about Neutralization Reaction from the given link:

https://brainly.com/question/15255706

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