Answer:
[tex]2x^2 -5x - 7 =0[/tex]
Step-by-step explanation:
We have the equation
[tex]x + 9 = 2(x-1)^2[/tex]
[tex](x-1)^2 = x^2-2x+1[/tex] using the formula [tex]\left(a-b\right)^2=a^2-2ab+b^2[/tex]
[tex]x + 9 = 2(x^2-2x\cdot \:1+1^2)[/tex] = [tex]2x^2-4x+2[/tex]
Switch sides
[tex]2x^2-4x+2=x+9[/tex]
Subtract 9 from both sides
[tex]2x^2-4x+2 - 9=x+9-9[/tex]
[tex]2x^2 -4x -7 = x[/tex]
Subtract x on both sides
[tex]2x^2 - 4x -7 -x = 0[/tex]
[tex]2x^2 - 4x - x -7 = 0[/tex]
[tex]2x^2 -5x - 7 =0[/tex]
where
[tex]a = 2, b = -5, c = -7[/tex]
