According to the given statement:
When the switch is opened, the current flow for bulb B immediately stops. As a result, bulb B remained switched off from the moment it is reopened until a considerable amount of time has passed.
The completely charged capacitor will operate as an energy source for bulbs A and D, and a diminishing current will pass through them exponentially. According to the equations of something like a discharging capacitor, they initially burn brightly but eventually go out.
Two conductors that are close to one another and are isolated from one another make up a capacitor, a device storing storing electrical energy. The parallel-plate capacitor is a straightforward illustration of such a storage device.
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I understand that the question you are looking for is:
After the switch has been closed for a long time, the switch is then reopened. Describe the behavior of the three light bulbs from the time when the switch is reopened to a long time after the switch has been reopened. Make sure that your description includes a comparison of the brightness of the bulbs. Explain your reasoning.
a) Bulb A:
b) Bulb B:
c) Bulb D:
