Respuesta :

bharathparasad577

The Concentration of NaOH solution when NaOH solution was titrated with 25cm3 of a 0.75mol/dm3 HNO3 is 26.4 g/dm3.

  • Titration is a method of chemical analysis where the quantity of a sample's constituents is determined by adding a precisely measured amount of a different substance to which the desired constituent will react in a specific, known proportion.

Given,

Volume of HNO3 is 25cm³ = 0.025 dm³

Amount of solute in mol = concentration in mol/dm3 × volume in dm3

Amount of HNO3 = 0.75 × 0.025 = 0.018 mol

The balanced equation is: NaOH(aq) + HNO3(aq) → NaNO3(aq) + H2O(l)

So the mole ratio NaOH:HNO3 is 1:1

Therefore 0.018 mol of NaOH reacts with 0.018 mol of HNO3.

Volume of sodium hydroxide solution 27.20cm³ =

0.027 dm³.

Concentration = 0.018 / 0.027 = 0.66 mol/ dm³

Relative formula mass of NaOH= 40

Mass = relative formula mass × amount

Mass of HCl = 40 × 0.66

= 26.4

So concentration = 26.4 g/dm3

Therefore, concentration of NaOH is 26.4 g/dm3

Learn more about Titration here:

https://brainly.com/question/186765

#SPJ9

Otras preguntas