Respuesta :
The molarity of a NaOH solution is 0.273
How do we find the Molarity of NaOH solution?
The molarity of the NaOH solution used in the neutralization reaction has been 0.273 x [tex]10^{-3}[/tex] M.
The neutralization reaction has resulted in the formation of the salt and water on reacting an acid with a base. In the neutralization reaction, the strength of acid and base can be given as
For the neutralization of 1 mole of sulfuric acid, 2 moles of NaOH have been required.
[tex]2NaOH + H2SO4[/tex] →[tex]Na2SO4 + H2O[/tex]
The moles of sulfuric acid can be given as:
Moles = Molarity × Volume
Given, the molarity of acid (H2SO4) = 0.220 M
The volume of acid = 15.5 ml = 0.0155 L
Volume of base (NaOH) = 25 ml = 0.025 L
Moles of H2S04 = 0.220× 0.0155mol
Moles of H2SO4 = 3.41 mol.
Since 1 mole of H2SO4 = 2 moles NaOH
3.14 moles of H2SO4 = 3.14 × 2 moles NaOH
3.14 moles of H2SO4 = 6.28 moles of NaOH.
The neutralization of 0.220 M H2SO4 requires 6.28 moles of NaOH. The strength of the NaOH solution will be:
Molarity =[tex]\frac{Moles}{Volume(L)}[/tex]
Molarity = [tex]\frac{6.28}{0.025}[/tex]
The molarity of a NaOH solution is 0.273
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