Respuesta :
The lower value of the calculated amount of water is the theoretical yield and the reactant that is used to calculate the theoretical yield is the limiting reactant. By looking at the calculations, we can say that the theoretical yield of the reaction is ≈1.9 g while the limiting reactant is NaOH.
How are the limiting reactant and theoretical yield determined?
- The theoretical yield of the reaction is 1.9 g, and the limiting reactant is NaOH.
- We can do so by converting both reactant masses to moles and then identifying the limiting reactant using one or more mole ratios from the balanced equation. The amount of the limiting reactant can then be used to calculate the theoretical yield of A l C l X 3 ceAlCl3 AlClX3.
- Multiply the number of moles of water by the water's molar mass. 2 + 16 = 18 g/mol is the molar mass. When multiplied by the product, this gives 0.834 moles H2O x 18 g/mol H2O = 15 grams. The theoretical water yield for this experiment is 15 grams.
To learn more about theoretical yield refer to
https://brainly.com/question/6258301
#SPJ4