The natural abundance of each isotope of lithium:
For [tex]^{6} Li[/tex] = 7.5%
For [tex]^{7} Li[/tex] = 92.5%
Due to the fact that lithium only has two stable isotopes, it follows that only two isotopes contribute to its average atomic mass.
Then, if we take x the proportional abundance of [tex]^{6} Li[/tex] it is possible to state that the decimal abundance of [tex]^{7} Li[/tex] need to be equivalent to 1−x.
Lithium's typical atomic mass will now be equal to =
avg. Atomic weight Li = Atomic weight of [tex]^{6} Li[/tex]× quantile abundance of [tex]^{6} Li[/tex]+ Atomic weight of [tex]^{7} Li[/tex]× quantile abundance of [tex]^{7} Li[/tex]
Since you are aware that the average atomic mass of lithium is
6.941 you can construct the equation as follows.
6.941 = 6.015 × x + 7.016 × (1-x)
x = 0.075
This is the decimal abundance of [tex]^{6} Li[/tex]. The decimal abundance of [tex]^{7} Li[/tex] is 1 - 0.075 = 0.925.
Percent abundances :
For [tex]^{6} Li[/tex] = 7.5%
For [tex]^{7} Li[/tex] = 92.5%
Learn more about isotope of lithium here;
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