A cube 5.0 cmcm on each side is made of a metal alloy. after you drill a cylindrical hole 2.5 cmcm in diameter all the way through and perpendicular to one face, you find that the cube weighs 6.30 nn.

Respuesta :

Therefore, the cube weighed 7.24 N before you punched a hole in it.

The metal's density is 197.15 cm3 (197.15 106 m3) in the cylindrical hole of the M/V formula. Therefore, = m/V" = W/gV"

Thus, by changing the variable values in the equation, we get the following result: = W/gV" = 0.00342 106 kg/m3 = 3420 kg/m3

Therefore, the metal's density is = 3420 kg/m3.

The cube's weight before drilling a hole. Before you put a hole into the cube, it weighed 7.24 N W = mg where m = mass of cube before drilling hole = V where = density of cube = 3420 kg/m3 and V = initial volume of cube = 216 cm3 = 216 106 m3 and g = acceleration due to gravity = 9.8 m/s2 we have

W=Vg W=3420 kg/m3, 216 106 m3, 9.8 m/s2, and 7.24 n

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