Respuesta :
userVals[i][j] < minVal / minVal = userVals[i][j] XXX and YYY will find the minimum value of all the elements in the array Choices are in the form XXX / YYY.
int userVals[NUM_ROWS][NUM_COLS];
int minVal = userVals[0][0];
for (i = 0; i < NUM_ROWS; ++i) {
for (j = 0; j < NUM_COLS; ++j) {
if (XXX) {
YYY;
}
}
}
We often need to find the minimum value in an array of numbers. There are a few different ways to do this, but the most straightforward is to use a for loop.
We start by assuming that the first element in the array is the minimum. Then, we compare this value to every other element in the array. If we find a smaller number, we know that this is the new minimum.
Here's the code:
int userVals[NUM_ROWS][NUM_COLS];
int minVal = userVals[0][0];
for (i = 0; i < NUM_ROWS; ++i) {
for (j = 0; j < NUM_COLS; ++j) {
if (userVals[i][j] < minVal) {
minVal = userVals[i][j];
}
}
}
You can see that we're just looping through all the elements in the array and keeping track of the smallest number we've seen so far.
There are a few different ways to find the minimum value in an array, but this is the most straightforward. Give it a try the next time you need to find the minimum value in an array!
Learn more on array here:
https://brainly.com/question/28565733
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