The moment of inertia of the propeller will be "0.3058 k.gm²"
Given.
Angle of rotation, = 124 rad/s
Work completed, W = 2351.3 J
The Work-Energy Principle is used as,
Kinetic energy Equals Net work done; (W) = (K.E)
We are aware,
→ K.E = × l × ω²
then,
→ W = × l × ω²
By exchanging the values, we obtain
2351.3 = × l × (124)²
thus, The moment of inertia,
I = 2351.3 × 2/[tex]124^{2}[/tex]
= 0.3058 k.gm²
The moment of inertia of the propeller will be "0.3058 k.gm²"
Learn more about moment of inertia here;
https://brainly.com/question/15246709
#SPJ4
