Two tents are in the shape of hemispheres, with circular floors. The ratio of their floor areas is 9: 12.25 . If the diameter of the smaller tent is 6 feet, what is the volume of the larger tent? Round to the nearest tenth.

Respuesta :

The volume of the larger tent in the shape of hemispheres, with circular floors, is 89.8 cubic feet.

If the diameter of the smaller tent is 6 feet, then its radius is 3 feet. Solving for the area of its circular floor,

A = πr^2

A = π(3 feet)^2

A = 9π square feet

Using the ratio of the floor areas of the two tents, calculate the area of the circular floor of the larger tent.

9 : 12.25 = 9π square feet : x

where x = area of the circular floor of the larger tent

9x = 12.25(9π)

x = 12.25 π square feet

If the area of the circular floor of the larger tent is 12.25 π square feet, then solving for its radius,

A = πr^2

12.25 π square feet = πr^2

r = 3.5 feet

Hemisphere refers to half of a sphere and its volume is given by the formula V = 2/3πr^3, where r is the radius.

V = 2/3πr^3

V = 2/3 π (3.5 feet)^3

V = 89.79719002 cubic feet

Rounding off to the nearest tenth.

V = 89.8 cubic feet

To learn more about volume of hemisphere: https://brainly.com/question/20325143

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