Two similar spheres have radii of 20 \pi meters and 6 \pi meters. What is the ratio of the surface area of the large sphere to the surface area of the small sphere?
A. 100/3 B. 100/9 C. 10/3 D. 10/9

Respuesta :

The ratio of the surface area of the large sphere to the surface area of the small sphere of radius 20π meters and 6π meters, respectively, is B. 100/9.

Surface area refers to the total area covering the outside of a three dimensional shape. The surface area of a sphere is given by the formula:

A = 4πr^2

Solving for the surface area of each sphere:
1. larger sphere, r = 20π meters

A = 4πr^2

A = 4π(20π meters)^2

A = 4π(400π^2 square meters)

A = 1600π^3 square meters

2. smaller sphere, r = 6π meters

A = 4πr^2

A = 4π(6π meters)^2

A = 4π(36π^2 square meters)

A = 144π^3 square meters

Getting the ratio of the surface area of the large sphere to the surface area of the small sphere:

1600π^3 square meters / 144π^3 square meters = 100/9

To learn more about surface area of sphere: https://brainly.com/question/1293273

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