The equation for the nth term of the arithmetic sequence is (6n – 1)
The given arithmetic progression is 5,11,17,23
Here we have been given
a = 5
d = a2 – a1
= 11 – 5
d = 6
The formula for the nth term is given as follows:
an = a + (n-1)d (1)
where, a = first term
d = common difference
putting the required values of ‘a’ and ‘d’ in equation (1) we get
an = 5 + (n-1)6
an = 5 + 6n – 6
an = 6n – 1
which is the required equation for the nth term of the arithmetic sequence
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