Respuesta :
The partial pressure of helium (He) in the mixture containing 1 g of H₂ and 1 g of He is 0.16 atm
What is Partial pressure?
Partial pressure can be explained if each specific gas contributes a part of the total pressure and that part is the partial pressure of that gas.
At first to find Mole For H₂:
Mass of H₂ = 1 g
Molar mass of H₂ = 2 × 1 = 2 g/mol
Mole of H₂ =?
Mole = mass / molar mass
Mole of H₂ = 1/2
Mole of H₂ = 0.5 mole
To find the mole For He:
Mass of He = 1 g
Molar mass of He = 4 g/mol
Mole of He =?
As we know, Mole = mass / molar mass
Mole of He = 1/4
Mole of He = 0.25 mole
Total Mole = Mole of Hydrogen+ Helium
Total mole = 0.5 + 0.25
Total mole = 0.75 mole
Next, we shall determine the mole fraction of He.
Mole fraction = mole / total mole
Mole of He = 0.25 mole
Total mole = 0.75 mole
Mole fraction of He = 0.25 / 0.75
Mole fraction of He = 0.33
To determine the partial pressure of He.
Partial pressure = mole fraction × total pressure
Mole fraction of He = 0.33
Total pressure = 0.48 atm
Partial pressure of He = 0.33 × 0.48
Partial pressure of He = 0.16 atm
Therefore, the partial pressure of helium (He) in the mixture is 0.16 atm
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