An unbiased coin is tossed 14 times. in how many ways can the coin land tails either exactly 8 times or exactly 2 times?

How many other directions can the land Tails also go? Eight times, and two games, exactly. Therefore, the likelihood of it happening is equal to 14 C. 8 P. To the powers of eight and Q, and six. Thus, the odds of success are one to two, and the odds of failure are also one to two. Therefore, 14 C. 81 by two to the 14th. In other words, that will be 14 13 12 14 18 plus other other times two. Therefore, the likelihood to end U will be 14 c. 2. All power to you. Oh okay So that's okay. Thus, we obtain 14 C. Two one times two to their benefit. single automobile Let me now resolve it. Okay, so if we consistently obtain 14 in 213 12 to work will start being permitted into two plus 14 12 11 and 2 are in 213 Then, in Mhm. one x two to the power 14 in 29 divided by six factorial six five full.33 multiplied by 91/2 to the power of 14. As a result, 191 in 234 will equal 40 when divided by 2. Therefore, 91 in 234 divided by 2 to the power 14 will be the answer to the discussion. Therefore, there was no use in dating at all. Therefore, the situation's solution—which also happens to be the solution with 0.1888, the required chance to obtain all of these solutions—clears your doubt. Thank you. So it will work out well, 91 plus 6-12, 5 to 10, 3329 2, shut out 2 to 4, and 2 7–14. And by this, these two will start to roll. Okay, so we convert 13 and 7-91 to 11 and 2. taking 91 once more, lady 33 multiplied by 91/2 to the power of 14. As a result, 191 in 234 will equal 40 when divided by 2. Therefore, 91 in 234 divided by 2 to the power 14 will be the answer to the discussion. Therefore, there was no use in dating at all. Therefore, the situation's solution—which also happens to be the solution with 0.1888, the required chance to obtain all of these solutions—clears your doubt.

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