122.67 ml of LiOH are required to reach the halfway point.
The balanced equation for the reaction of lithium hydroxide with the acid:
LiOH + HCOOH → HCOOLi + H₂O
V(HCOOH) = 46.0 ml; volume of the acid
c(HCOOH) = 0.400 M; concentration of the acid
c(LiOH) = 0.150 M; concentration of lithium hydroxide
V(LiOH) = ?; volume of lithium hydroxide
At the halfway point: n(HCOOH) = n(LiOH)
c(HCOOH) × V(HCOOH) = c(LiOH) × V(LiOH)
0.400 M × 46.0 ml = 0.150 M × V(LiOH)
V(LiOH) = 0.400 M × 46.0 ml / 0.150 M
V(LiOH) = 122.67 ml; volume of lithium hydroxide
More about neutralization: brainly.com/question/23008798
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