347.8 grams of sodium hydroxide will be formed.
Balanced chemical equation for reaction of sodium with water:
2Na + 2H₂O → 2NaOH + H₂
m(Na) = 200 g; mass of sodium
M(Na) = 23 g/mol; molar mass of sodium
n(Na) = m(Na) ÷ M(Na).
n(Na) = 200 g ÷ 23 g/mol.
n(Na) = 8.695 mol; amount of sodium.
From chemical equation: n(Na) : n(NaOH) = 1 : 1.
n(NaOH) = 8.695 mol; amount of sodium hydroxide
M(NaOH) = 40 g/mol; molar mass of sodium hydroxide
m(NaOH) = 8.695 mol × 40 g/mol
m(NaOH) = 347.8 g; mass of sodium hydroxide
More about stoichiometry: brainly.com/question/16060199
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